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2450=x^2-x
We move all terms to the left:
2450-(x^2-x)=0
We get rid of parentheses
-x^2+x+2450=0
We add all the numbers together, and all the variables
-1x^2+x+2450=0
a = -1; b = 1; c = +2450;
Δ = b2-4ac
Δ = 12-4·(-1)·2450
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-99}{2*-1}=\frac{-100}{-2} =+50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+99}{2*-1}=\frac{98}{-2} =-49 $
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